Problem (Piskunov Vol. 1, Chapter 1, §4): Evaluate the following limit: $$ \lim_x \to 0 \frac\sqrt1+x - 1x $$
Solution:
Step 1: Identify the Indeterminacy If we substitute $x = 0$ directly, we get: $$ \frac\sqrt1+0 - 10 = \frac1 - 10 = \frac00 $$ This is an indeterminate form, so we must use algebraic manipulation to resolve it.
Step 2: Rationalize the Numerator Multiply the numerator and the denominator by the conjugate of the numerator ($\sqrt1+x + 1$): solucionario de piskunov pdf
$$ \lim_x \to 0 \frac\sqrt1+x - 1x \cdot \frac\sqrt1+x + 1\sqrt1+x + 1 $$
Step 3: Simplify the Expression In the numerator, we have the product of a sum and difference: $(a-b)(a+b) = a^2 - b^2$. Here, $(\sqrt1+x)^2 - (1)^2 = (1+x) - 1 = x$.
So the expression becomes: $$ \lim_x \to 0 \fracxx(\sqrt1+x + 1) $$ ¿Para qué sirve realmente el solucionario
Step 4: Cancel Common Terms We can cancel $x$ from the numerator and denominator (since $x \neq 0$ as we are calculating the limit): $$ \lim_x \to 0 \frac1\sqrt1+x + 1 $$
Step 5: Evaluate the Limit Now, substitute $x = 0$: $$ \frac1\sqrt1+0 + 1 = \frac11 + 1 = \frac12 $$
Answer: $$ \frac12 $$
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